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Geometry and Trigonometry Difficulty: Hard

An isosceles right triangle has a perimeter of 94 + 94 2 inches. What is the length, in inches, of one leg of this triangle?

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Explanation

Choice B is correct. It's given that the right triangle is isosceles. In an isosceles right triangle, the two legs have equal lengths, and the length of the hypotenuse is 2 times the length of one of the legs. Let l represent the length, in inches, of each leg of the isosceles right triangle. It follows that the length of the hypotenuse is l2 inches. The perimeter of a figure is the sum of the lengths of the sides of the figure. Therefore, the perimeter of the isosceles right triangle is l+l+l2 inches. It's given that the perimeter of the triangle is 94+942 inches. It follows that l+l+l2=94+942. Factoring the left-hand side of this equation yields 1+1+2l=94+942, or 2+2l=94+942. Dividing both sides of this equation by 2+2 yields l=94+9422+2. Rationalizing the denominator of the right-hand side of this equation by multiplying the right-hand side of the equation by 2-22-2 yields l=94+9422-22+22-2. Applying the distributive property to the numerator and to the denominator of the right-hand side of this equation yields l=188-942+1882-9444-22+22-4. This is equivalent to l=9422, or l=472. Therefore, the length, in inches, of one leg of the isosceles right triangle is 47 2 .

Choice A is incorrect and may result from conceptual or calculation errors.

Choice C is incorrect. This is the length, in inches, of the hypotenuse.

Choice D is incorrect and may result from conceptual or calculation errors.